求解答过程：阅读理解.
The wedding took place in a Birmingham hotel. The bride and her father arrived in a new black American sports car. Her father looked nervous and uncomfortable in front of the cameras. The bride _百度作业帮
求解答过程：阅读理解.
The wedding took place in a Birmingham hotel. The bride and her father arrived in a new black American sports car. Her father looked nervous and uncomfortable in front of the cameras. The bride
求解答过程：阅读理解.
&&&& The wedding took place in a Birmingham hotel. The bride and her father arrived in a new black American sports car. Her father looked nervous and uncomfortable in front of the cameras. The bride wore a silk wedding dress. She smiled nervously at the waiting photographer and went to a room on the first floor where she met her future husband for the very first time.
&&&& Carla Germaine and Greg Cordell were the winners of a radio station's competition. The aim of the competition was to find two strangers prepared to marry without having met each other. Miss Germaine, 23,
is a model. Mr. Cordell, 27, is a TV salesman. They were among the two hundred people who entered for a
peculiar"experiment" organized by BMRB radio in Birmingham, England. Greg and Carla were among eight
finalists who were interviewed live on radio. They took a lie detector (测谎仪) test and the station also spoke to their friends and family about their personalities. The competition judges included an astrologer (占星家)
who declared that they were suited.
&&&& The couple celebrated their wedding with a wedding breakfast and a party for 100 guests in the evening, but not everyone shared their joy. Miss Germaine's mother looked anxious throughout the wedding and
Mr. Cordell's parents are reported to be less than delighted. Organizations, including the marriage guidance
service Relate, have criticized the marriage. As one person put it, "We have enough problems getting young people to take marriage seriously without this. Marriage should always be about love."
&&&& The couple are now on a Caribbean honeymoon followed by journalists. Their other prizes include a year's
free use of a wonderful apartment in the centre of Birmingham, and a car. But will it last?
1. &How did the couple's react to the wedding?
A. The bride's mother shared their joy. B. The bride's father felt uncomfortable about the wedding.
C. The bridegroom's parents were quite delighted.
D. The bridegroom's parents were not that joyful.
2. &Some experts believe that ______.
A. marriage without the couple's meeting each other first ends up in divorce
B. young people nowadays are too careless about marriage C. taking a lie detector test can not solve all the marriage problems
D. most young people take marriage seriously except this couple
3. &One of the prizes for the couple is ______.
A. to spend their honeymoon wherever they like
B. to use an apartment free for some time
C. to have a wedding dress free
D. to own an American sports car
4. &Which of the following is the best title of the passage?
A. Two Strangers and a Wedding
B. A Wedding Based on Love
C. A Short-Lived Marriage
D. A Well-Matched Coe upl连接,则与轴的交点即为所求的点,用待定系数法求出所在直线的解析式,再根据轴上点的坐标特点求出点坐标即可;因为),所以当时最小,即点在线段的垂直平分线上,设出点坐标,利用两点间的距离公式即可求解;因为当点在直线与轴的交点时,取等号这时绝对值最大,等于,所以用待定系数法求出过,两点的直线解析式,再把所设点坐标代入求解即可.
如图所示,连接,则直线交轴于点,设,过两点的直线为,则,解得,,故过,两点的一次函数的解析式为,把点代入一次函数的解析式得,解得,故点坐标为;因为),所以当时最小,故点在线段的垂直平分线上,作线段的垂直平分线交轴于点,则点即为所求,设,则,即,解得,故点的坐标为;作关于轴的对称点(也可以作关于轴的对称点,道理一样),这样始终等于的,点,,构成三角形,所以绝对值,其实右边可以去等号,也就是当点在直线与轴的交点时,取等号这时绝对值最大,等于,设,过两点的直线为,故,解得,,故过的一次函数解析式为,把代入得,,解得,故点坐标为.
本题考查的是最短线路问题及用待定系数法求一次函数的解析式,是一道综合性题目.
3969@@3@@@@轴对称-最短路线问题@@@@@@263@@Math@@Junior@@$263@@2@@@@图形的对称@@@@@@53@@Math@@Junior@@$53@@1@@@@图形的变化@@@@@@7@@Math@@Junior@@$7@@0@@@@初中数学@@@@@@-1@@Math@@Junior@@$3776@@3@@@@坐标与图形性质@@@@@@251@@Math@@Junior@@$251@@2@@@@平面直角坐标系@@@@@@51@@Math@@Junior@@$51@@1@@@@函数@@@@@@7@@Math@@Junior@@$7@@0@@@@初中数学@@@@@@-1@@Math@@Junior@@
@@53@@7##@@51@@7
第三大题，第5小题
求解答 学习搜索引擎 | 已知点A(1,3),B(5,-2),在x轴上找一点P,使(1)AP+BP最小;(2)|AP-BP|最小;(3)|AP-BP|最大.求解答集合题如图,正方形ABCD中,E为AB边上一点,过点D作DF⊥DE,与BC延长线交于点F．连接EF,与CD边交于点G,与对角线BD交于点H．（1）若BF=BD=√2（根号2）
,求BE的长；（2）若∠ADE=2∠BFE,求证：FH=H_百度作业帮
求解答集合题如图,正方形ABCD中,E为AB边上一点,过点D作DF⊥DE,与BC延长线交于点F．连接EF,与CD边交于点G,与对角线BD交于点H．（1）若BF=BD=√2（根号2）
,求BE的长；（2）若∠ADE=2∠BFE,求证：FH=H
求解答集合题如图,正方形ABCD中,E为AB边上一点,过点D作DF⊥DE,与BC延长线交于点F．连接EF,与CD边交于点G,与对角线BD交于点H．（1）若BF=BD=√2（根号2）& &,求BE的长；（2）若∠ADE=2∠BFE,求证：FH=HE+HD．
（1）由四边形ABCD正方形,BF=BD= 2,由勾股定理即可求得BC的长,又由DF⊥DE,易证得△ADE≌△CDF,即可求得BE的长；（2）首先在FE上截取一段FI,使得FI=EH,由△ADE≌△CDF,易证得△DEH≌△DFI,即可得DH=DI,又由∠ADE=2∠BFE,易证得△DHI为等边三角形,即可得DH=HI,继而可得FH=HE+HD．∵四边形ABCD正方形,∴∠BCD=90°,∴Rt△BCD中,BC2+CD2=BD2,即BC2=（2）2+（2）2,∴BC=AB=1,∵DF⊥DE,∴∠ADE+∠EDC=90°=∠EDC+∠CDF,∴∠ADE=∠CDF,在△ADE和△CDF中,∵∠ADE=∠CDFAD=DC∠A=∠DCF=90°​,∴△ADE≌△CDF（ASA）,∴AE=CF=BF-BC=2-1,∴BE=AB-AE=1-（2-1）=2-2；（2）证明：在FE上截取一段FI,使得FI=EH,∵△ADE≌△CDF,∴DE=DF,∴△DEF为等腰直角三角形,∴∠DEF=∠DFE=45°=∠DBC,∵∠DHE=∠BHF,∴∠EDH=∠BFH（三角形的内角和定理）,在△DEH和△DFI中,∵DE=DF∠DEH=∠DFIEH=FI​,∴△DEH≌△DFI（SAS）,∴DH=DI,又∵∠HDE=∠BFE,∠ADE=2∠BFE,∴∠HDE=∠BFE=12∠ADE,∵∠HDE+∠ADE=45°,∴∠HDE=15°,∴∠DHI=∠DEH+∠HDE=60°,即△DHI为等边三角形,∴DH=HI,∴FH=FI+HI=HE+HD．
（1）由四边形ABCD正方形，BF=BD= 2，由勾股定理即可求得BC的长，又由DF⊥DE，易证得△ADE≌△CDF，即可求得BE的长；（2）首先在FE上截取一段FI，使得FI=EH，由△ADE≌△CDF，易证得△DEH≌△DFI，即可得DH=DI，又由∠ADE=2∠BFE，易证得△DHI为等边三角形，即可得DH=HI，继而可得FH=HE+HD．（1）∵四边形ABCD正方形，<...上的大写锁定键&capslock&，再次按一下即可。
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那个人是第10个人，按理说电梯还没超重，但却显示超重，，表明里面其实已经有 10个人了。 那那个人看到电梯里只有9个人，那还有一个人在哪里呢？~~~然后再看三个...
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不碍事，停用了就行了，包括软件，找到他，这个是手机同步服务，你直接在应用程序里面，没啥用无所谓。 求采纳
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